(3x+2)(2x^2-4x+3)=0

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Solution for (3x+2)(2x^2-4x+3)=0 equation:


Simplifying
(3x + 2)(2x2 + -4x + 3) = 0

Reorder the terms:
(2 + 3x)(2x2 + -4x + 3) = 0

Reorder the terms:
(2 + 3x)(3 + -4x + 2x2) = 0

Multiply (2 + 3x) * (3 + -4x + 2x2)
(2(3 + -4x + 2x2) + 3x * (3 + -4x + 2x2)) = 0
((3 * 2 + -4x * 2 + 2x2 * 2) + 3x * (3 + -4x + 2x2)) = 0
((6 + -8x + 4x2) + 3x * (3 + -4x + 2x2)) = 0
(6 + -8x + 4x2 + (3 * 3x + -4x * 3x + 2x2 * 3x)) = 0
(6 + -8x + 4x2 + (9x + -12x2 + 6x3)) = 0

Reorder the terms:
(6 + -8x + 9x + 4x2 + -12x2 + 6x3) = 0

Combine like terms: -8x + 9x = 1x
(6 + 1x + 4x2 + -12x2 + 6x3) = 0

Combine like terms: 4x2 + -12x2 = -8x2
(6 + 1x + -8x2 + 6x3) = 0

Solving
6 + 1x + -8x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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